Balance equations and use the mole to run stoichiometry, limiting reagents and yield.
ExperimentsWeigh a reactionBurn something and find out how many atoms go with each other.
Experiment 1 · Lavoisier, 1770s; Proust, 1790s
Burning magnesium
Burn a ribbon of magnesium and weigh what is left. Where does the extra mass come from, and how much is there?
In the 1770s Antoine Lavoisier weighed everything that went into a reaction and everything that came out, and found the totals matched: when a metal burns it gains weight from the air. In 1799 Joseph Proust argued that a compound always contains its elements in the same proportion by mass, and spent years in dispute with Claude Berthollet over it. Chemistry needs to count atoms, which are far too small to count, but weighing the products of a reaction can tell you what it does. Burn magnesium, weigh the ash, and find how many atoms of oxygen go with each atom of magnesium. (We cannot repeat Proust's balance, so the masses here are simulated from the atomic masses, with the scatter of a good laboratory balance.)
0 trials, 0 different amounts
Step 1 of 2 · Burn different amountsDrag the marker to choose an amount of magnesium and burn it. Do this with three different amounts and look at the graph.
Ash ÷ metal (mean)—
Moles of Mg (last)—
Moles of O gained—
Ratio O : Mg—
The maths
Law of conservation of mass: the ash (MgO) weighs the metal plus the oxygen it took from the air. mass of oxygen = mass of ash − mass of metal.
Questions you might have (4)Why is the ash heavier than the metal?
Magnesium burns by combining with oxygen in the air. The product, magnesium oxide, contains both. Weighed alone, the metal has lost nothing: it has gained the weight of the oxygen. This is what Lavoisier showed for burning in general, against the older idea that burning released a substance (phlogiston) and so should make things lighter.
Is this the law of definite proportions?
Yes. Joseph Proust argued in the 1790s that a given compound always has the same elements in the same proportion by mass, however it is made. Magnesium oxide from any source is 60.3 % magnesium by mass, and so the ash is always 1.658 times as heavy as the metal.
Why divide by the atomic mass?
Equal masses of different elements hold different numbers of atoms, because the atoms have different masses. 24.3 g of magnesium and 16.0 g of oxygen hold the same number of atoms. Dividing a mass by the atomic mass gives a number proportional to the number of atoms, which is what a formula is about.
Are these real measurements?
No: they are simulated. Each result is computed from the atomic masses in the course's table of elements, with a random scatter of about 0.4 %, roughly what a careful student gets on a school balance. The scatter is why the points do not fall exactly on the line.
Run the experiment to see what it showed.
TheoryCounting by weighingA unit that turns grams into atoms.
Theory 1 · Avogadro, 1811
The mole
How many atoms are in a pile of copper? You cannot count them, but you can weigh them. How do you turn a mass into a count?
In 1811 Amedeo Avogadro proposed that equal volumes of gas hold equal numbers of molecules, but nobody could say how many. In the first years of the twentieth century Jean Perrin measured that number in many different ways, from the motion of tiny particles in water to the charge of the electron, and got the same answer each time. That convinced the last doubters that atoms are real. The number is huge, and it comes with a unit, the mole. Find out what it counts: drag each sample to the mass you think holds one mole of atoms.
Step 1 of 2 · One mole of eachDrag each marker to the mass you think holds the same number of atoms as 12.011 g of carbon. The dots count the atoms; a row turns green when it holds one mole, to within 2 %.
Avogadro's number6.02214 × 10²³
Samples at one mole0 / 4
Atoms in a mole of Au6.022e+23
The maths
moles = mass ÷ molar mass number of atoms = moles × N_A, N_A = 6.02214076 × 10²³ per mole
6.022 × 1023 is how many in a mole: a number defined exactly, since 2019, as the count that makes the mole link grams to atoms.
Questions you might have (4)How big is 6.022 × 10²³?
A mole of water is only 18 g, about a tablespoon, and it holds 6.022 × 10²³ molecules. If a million people counted a million molecules every second, it would still take them about 19,000 years. The number is huge because atoms are tiny, and it is chosen so that the mass of a mole in grams comes out as a number you can handle.
Why is it called the mole, and who counted it?
The word comes from the German Mol, short for Molekül, and was introduced around 1900 by Wilhelm Ostwald. The number was first estimated from experiments such as the oil-drop measurement of the electron's charge combined with electrolysis (the charge on a mole of electrons divided by the charge of one): from this section onward, that is the number you use.
Why does the molar mass match the atomic mass number?
By definition, the mole was set up so that one mole of carbon-12 weighs 12 g (now fixed through Avogadro's number). The atomic mass of an element on the periodic table is its average mass in atomic mass units (u), and the same number is its mass in grams per mole.
What about compounds?
Add up the atomic masses in the formula. Water, H₂O, is 2 × 1.008 + 15.999 = 18.015 g/mol. A mole of water is 6.022 × 10²³ molecules and weighs 18.015 g. Ethanol, glucose and any other compound work the same way.
Work through it to see what it shows.
TheoryThe recipeAn equation that counts atoms is an equation that counts moles.
Theory 2 · Lavoisier, 1789
Balancing an equation
Lavoisier weighed everything that went into a reaction and everything that came out, and they matched. What does that say about atoms?
In 1789 Lavoisier published the principle that matter is neither created nor destroyed in a chemical reaction, and he said it as an equation: what you start with equals what you end with. An equation that obeys him has the same atoms on both sides, and the whole numbers that make it so are the recipe. This is a pencil skill. Work the problems below on paper, and use the boxes to check your coefficients.
How it is done: the method and a worked example
The method
Write the formulas down and make a table of the atoms of each element on each side.
Start with an element that appears in only one place on each side. Leave oxygen or hydrogen, which are often in several places, for last.
Change a coefficient, update the table, and repeat. If you end with a fraction, double everything. Finish by checking every element.
A worked example: rusting, Fe + O₂ → Fe₂O₃
Fe + O₂ → Fe₂O₃
atom
left
right
Fe
1
2 ✗
O
2
3 ✗
Step 1: Count the atoms as written. Fe: 1 on the left, 2 on the right. O: 2 on the left, 3 on the right. Neither agrees.
The worksheet: balance these on paper, then check
Type your coefficients into the boxes (whole numbers, smallest possible) and press Check. 7 of 10 correct finishes the section.
1. Hydrogen burning in air, the reaction Cavendish and Lavoisier used to show that water is a compound.
H₂+O₂→H₂O
2. The Haber process, which feeds roughly half the world through fertilizer.
N₂+H₂→NH₃
3. Sodium dropped in water, a favourite of every demonstrator.
Na+H₂O→NaOH+H₂
4. Natural gas on the stove.
CH₄+O₂→CO₂+H₂O
5. Bottled gas on the barbecue.
C₃H₈+O₂→CO₂+H₂O
6. Aluminum dissolving in hydrochloric acid.
Al+HCl→AlCl₃+H₂
7. Slaked lime with phosphoric acid: the brackets move as units.
Ca(OH)₂+H₃PO₄→Ca₃(PO₄)₂+H₂O
8. Thermite, Goldschmidt, 1893: aluminum takes the oxygen from iron oxide so violently that the iron comes out molten.
Al+Fe₂O₃→Al₂O₃+Fe
9. The sugar your body burns.
C₆H₁₂O₆+O₂→CO₂+H₂O
10. Petrol. Oxygen comes out as a fraction: what do you do?
C₈H₁₈+O₂→CO₂+H₂O
Worksheet · 0 of 7 correctWork an equation on paper first, then enter its coefficients and press Check. After a wrong answer, the notebook below lists atoms on each side.
Correct0 / 10
Needed7
Shown the answer0
The maths
Atoms are conserved: every element must appear the same number of times on both sides. Change only the coefficients, never the subscripts.
Questions you might have (4)Why can't I just change the subscripts?
A subscript is part of the identity of a substance. H₂O is water; H₂O₂ is hydrogen peroxide, a different compound. Changing a subscript describes a different reaction. A coefficient only says how many of the molecules there are.
What do I do when oxygen comes out as a fraction?
Octane gives 25/2 O₂. Multiply every coefficient by 2 to clear it. The result, 2 C₈H₁₈ + 25 O₂ → 16 CO₂ + 18 H₂O, is a perfectly good equation: coefficients count molecules in the recipe, and two molecules of octane burn together.
Why do I leave oxygen for last?
It appears in several formulas, so changing its coefficient early disturbs the other elements. Balance the elements that appear once on each side first, and oxygen usually comes out right at the end.
Does a balanced equation conserve mass?
Yes. Add the molar masses times the coefficients on each side, as the notebook does after a correct answer, and they match. That is Lavoisier's result, and the fact that makes the mass calculations in the next section possible.
Work through it to see what it shows.
ExperimentsAn unknown, and a furnaceFind a formula by burning the compound and weighing the products.
Experiment 2 · Liebig, 1830s
What is the unknown?
A bottle holds a compound of carbon, hydrogen and oxygen. Burn a gram of it and weigh what comes out. What is its formula?
In the early 1830s Justus Liebig designed an apparatus to burn a weighed sample of an organic compound completely and catch the water and carbon dioxide in separate tubes. All the carbon ends up in one tube and all the hydrogen in the other, so weighing them gives the formula. It made organic chemistry a matter of balances instead of guesses. The burning magnesium gave a formula from two masses. Here is the same idea for compounds you can burn but cannot take apart. (The masses are simulated from the true compounds, with 0.3 % scatter.)
Sample:
Step 1 · Burn itBurn the unknown and read the two masses. Then work through the analysis, step by step, with the buttons.
Sample0.5 g
CO₂ collected—
H₂O collected—
Identified0 / 3
The maths
Burn the sample completely in oxygen: every C ends up in CO₂, every H in H₂O. Whatever mass is left over, after C and H, was oxygen.
Questions you might have (4)Why is the oxygen found by difference?
The oxygen in the sample leaves as CO₂ and H₂O together with the oxygen from the furnace, so the products' oxygen cannot be used. But the carbon and hydrogen in the sample are fully accounted for, so whatever mass of the sample is not C or H must be something else, here oxygen. A compound with nitrogen or sulfur needs more measurements.
Why is the empirical formula not always the molecular formula?
The method counts atoms in proportion, not in absolute numbers. Ethylene glycol is C₂H₆O₂, whose simplest ratio is CH₃O; acetic acid is C₂H₄O₂, simplest ratio CH₂O, the same as glucose, C₆H₁₂O₆. They differ in molar mass, and that is what separates them.
What does the 0.3 % scatter do?
Real masses are never exact, so the mole ratios come out near whole numbers but not on them: 2.01 and 5.98, not 2 and 6. You round to the nearest whole-number ratio, and if a ratio looks like 1.5 you multiply everything by 2.
Is propane an interesting case?
Yes: it contains no oxygen, so the oxygen found by difference is close to zero. The method says so, and the formula comes out as C₃H₈ without any oxygen.
Run the experiment to see what it showed.
TheoryFrom any mass to any otherThe recipe, run forwards and backwards.
Theory 3 · Richter, 1792
Weighing becomes counting
You have 4.0 g of hydrogen. How much water can it make? And how much hydrogen do you need to make 36 g?
In 1792 Jeremias Richter, a German chemist, noticed that when an acid and a base neutralise one another the masses that react follow fixed ratios, and he coined the word stoichiometry for the measuring of such things. You can count atoms by weighing, and a balanced equation says how many of each react. Put the two together and the mass of one substance fixes the mass of every other. Build the chain of conversions yourself, so that the units cancel, and run it forwards and backwards.
Problem:
2 H₂ + O₂ → 2 H₂O
You have 4 g of H₂. How many grams of H₂O can it make?
4 g H₂=? g H₂O
Choose the next conversion factor. Each one is a fraction equal to 1, written so that the unit you hold (g H₂) cancels.
Problem 1 of 4 · run it forwardsBuild the chain from three conversion factors: first from grams to moles, then from moles to moles using the coefficients, then from moles to grams.
Starting from4 g H₂
Answer?
Moles of H₂1.984
Solved0 / 4
The maths
g → mol (÷ molar mass) → mol → mol (coefficients) → mol → g (× molar mass). Each factor is chosen so that the unit above cancels the unit below.
2 H₂ + O₂ → 2 H₂O
4 g H₂
Questions you might have (4)Why does the mole ratio use the coefficients and not the masses?
The coefficients count molecules (and so moles); they do not count grams. In 2 H₂ + O₂ → 2 H₂O, two moles of hydrogen react with one mole of oxygen, but those are 4.03 g and 32.0 g. The masses are different because the molar masses are different. Converting to moles first puts everything on the same footing.
How do I know which way to put each factor?
By the units. Write down the unit you have and the unit you want, and choose the factor with the unit you have on the bottom, so it cancels. If the units do not cancel, the factor is upside down. The bench refuses a factor that does not cancel.
Does this work for any reaction?
Any balanced equation. The same three steps work whatever the substances are, whether they are solids, liquids or gases, as long as you know their formulas to get molar masses, and the balanced equation for the coefficients.
What if the amounts are not in the ratio of the recipe?
Then one reactant runs out first, and it limits how much product can form. That is the limiting reagent, the subject of the last experiment of this unit.
Work through it to see what it shows.
ExperimentsWhen the ingredients do not matchRun out of one, and the reaction stops.
Experiment 3 · Every reaction ever run
Which ingredient runs out first?
A recipe needs 2 parts hydrogen to 1 part oxygen. What happens if you do not have that mix?
In 1909 Fritz Haber made ammonia from nitrogen and hydrogen on a laboratory bench, and by 1913 Carl Bosch had scaled the process up to a factory. The engineer's question is not what the equation says but how much ammonia the tanks will give. Real mixtures do not come in the ratio of the recipe: one ingredient runs out first. Mix hydrogen and oxygen in several amounts, react them, and see what is used up and what is left. Then do it in grams, where the answer is what a chemist wants: how much can I make?
Mixture:2 H₂ + O₂ → 2 H₂O
hydrogen, H₂: 6
oxygen, O₂: 5
water, H₂O: 0
Which runs out first?
Step 1 of 3 · Three mixturesChoose each mixture, predict which reactant runs out first, then react. Do all three. 0 of 3 done.
Mixture6 H₂, 5 O₂
Limiting reagent?
Theoretical yield, NH₃?
Percent yield?
The maths
The reactant that runs out first, the limiting reagent, decides how much product forms. Divide each amount of reactant by its coefficient: the smallest quotient limits.
6 H₂ and 5 O₂: H₂ 6 ÷ 2 = 3, O₂ 5 ÷ 1 = 5. H₂ limits; the equation runs 3 times and leaves 2 O₂.
Questions you might have (4)Why divide by the coefficient?
Because the coefficient says how many moles of that reactant one run of the equation uses. Dividing moles by it gives how many runs that reactant could supply. The reactant that supplies the fewest runs stops the reaction.
Is the reagent with less mass always the limiting one?
No. In the ammonia example the nitrogen weighs 28 g and the hydrogen only 5 g, yet it is the hydrogen that limits, because it is needed in three times the number of moles and a hydrogen molecule weighs so little. Always convert to moles first.
Why is the actual yield less than the theoretical?
Several reasons: the reaction may not go to completion (many reach an equilibrium), side reactions use some reactant, product is lost in transfers and filtering, and some is left in the apparatus. The 78 % here is chosen to look like a typical laboratory result.
Could the percent yield be over 100 %?
Not if everything is done correctly. If it is, the product is wet with solvent, contaminated with another substance, or was weighed wrongly. It is a useful warning sign.
Run the experiment to see what it showed.
PracticeProblemsNumbers from this unit, in the style of a college problem set.
Practice
Practice
Numbers from the experiments, in the style of a college problem set. Every problem has a hint and a worked solution.